Question

derivar
$y = \frac{ - {x}^{3} }{7}$

$f(x) = \frac{ \sqrt{ {x}^{3} } }{9}$

$y = - 5 \frac{ \sqrt{ {a}^{2} {x}^{4} } }{a}$

$y = \frac{ {3}^{5} - 2 {x}^{3} + 4x}{3}$

$y = \frac{2}{ {x}^{4} } + \frac{3 {x}^{5} }{4} - 4 {x}^{ - 3}$

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Answer 1

Respuesta:

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