Question

Demostrar que (tanu+cotu)(cosu+senu)=cscu+secu

Answer 1

(tan@+ctg@)(cos@+sen@)=

[(sen@/cos@)+(cos@/sen@)][cos@+sen@]=

[(sen²@+cos²@)/sen@cos@][cos@+sen@]=

(1/sen@cos@)(cos@+sen@)=

(cos@+sen@)/sen@cos@=

cos@/sen@cos@ + sen@/sen@cos@=

1/sen@ + 1/cos@=

csc@ + sec@


Espero te sirva.

Salu2.

Suerte... :)