de urge √(x-3) = √(5x-11) -4 el -4 esta fueras de la raiz
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√(x-3) = √(5x-11) - 4
[√(x-3)]² = [√(5x-11) - 4]²
x - 3 = 5x - 11 - 8√(5x-11) + 16
8√(5x-11) = 4x + 8
[8√(5x-11)]² = (4x+8)²
64(5x - 11) = 16x² + 64x + 64
4(5x - 11) = x² + 4x + 4
20x - 44 = x² + 4x + 4
x² - 16x + 48 = 0
(x - 12) (x - 4) = 0
x-12 = 0 ó x-4 = 0
x = 12 ó x = 4
[√(x-3)]² = [√(5x-11) - 4]²
x - 3 = 5x - 11 - 8√(5x-11) + 16
8√(5x-11) = 4x + 8
[8√(5x-11)]² = (4x+8)²
64(5x - 11) = 16x² + 64x + 64
4(5x - 11) = x² + 4x + 4
20x - 44 = x² + 4x + 4
x² - 16x + 48 = 0
(x - 12) (x - 4) = 0
x-12 = 0 ó x-4 = 0
x = 12 ó x = 4
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