Question

De 7x2+6x+11, restar 8x-6x2-11

De 9n3+4n2+9n-12, restar 5n3-5n2-12n+8

Answer 1

De 7x2+6x+11, restar 8x-6x2-11:

$(7x^{2}+6x+11)-(8x-6x^{2}-11)=7x^{2}+6x+11-8x+6x^{2}+11=(7+6)x^{2}+(6-8)x+(11+11)=x^{2}-2x+22$

De 9n3+4n2+9n-12, restar 5n3-5n2-12n+8:

$(9n^{3}+4n^{2}+9n-12)-(5n^{3}-5n^{2}-12n+8)=9n^{3}+4n^{2}+9n-12-5n^{3}+5n^{2}+12n-8=(9-5)n^{3}+(4+5)n^{2}+(9+12)n+(-12-8)=4n^{3}+9n^{2}+21n-20$