Question

dar el valor de a+b, si: 6a(a+3)=9° y 2a3bbb=11°

hallar el valor de m para que el numeral m235 sea11°

Answer 1

1)
$\overline{6a(a+3)}=9\°\Longrightarrow 6+a + a+3 =9\°\\ \overline{6a(a+3)}=9\°\Longrightarrow 2a+9 =9\°\\ \overline{6a(a+3)}=9\°\Longrightarrow a =9\°\\ \text{Entonces }\boxed{a\in\{0,9\}}\\ \\ \overline{2a3bbb}=11\°\Longrightarrow 2-a+3-b+b-b=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow 5-a-b=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow a+b-5=11\°\\\\ \text{Si }a=0\text{ entonces:}\\ \overline{2a3bbb}=11\°\Longrightarrow b-5=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow \boxed{b=5}$

$\text{Como }a+3\leq 9 \iff a\leq 6 \text{ entonces }\boxed{a+b=5}$

===========================================================

$m+2-3+5=11\°\\ m+4=11\°\\ m=11\°-4\\ \\ \boxed{m=7}$

Answer 2

seria esto dame corona

a=0 b=5

a+b=5