Dados 1000 mL de helio a 15 °C y 763 mmHg, determínese su volumen a – 6 °C y 420 mmHg
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203
P1 V1 = P2 V2
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T1 T2
V2 = P1 V1 T2
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P2 T1
V1 = 1000 mL = 1 L
P1 = 763 mmHg/760 = 1.004 atm
T1 = 15 + 273 0 288 K
V2 = ?
P2= 0.552 atm
T2 = -6 + 273 = 267 K
V2 = 1.004 atm x 1 L x 267 K
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0.552 atm x 288 K
V2 = 1.6862 L x 1000 = 1.6862 x 10³ mL
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T1 T2
V2 = P1 V1 T2
```````````````
P2 T1
V1 = 1000 mL = 1 L
P1 = 763 mmHg/760 = 1.004 atm
T1 = 15 + 273 0 288 K
V2 = ?
P2= 0.552 atm
T2 = -6 + 273 = 267 K
V2 = 1.004 atm x 1 L x 267 K
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0.552 atm x 288 K
V2 = 1.6862 L x 1000 = 1.6862 x 10³ mL
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Respuesta:
1.6862 L x 1000 = 1.6862 x 10³ mL
Explicación:
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