Question

da el valor de a + b si 6a(a+3)3 =9 y 2a3bbb=11

Answer 1

Respuesta:

\begin{gathered}\overline{6a(a+3)}=9\°\Longrightarrow 6+a + a+3 =9\°\\ \overline{6a(a+3)}=9\°\Longrightarrow 2a+9 =9\°\\ \overline{6a(a+3)}=9\°\Longrightarrow a =9\°\\ \text{Entonces }\boxed{a\in\{0,9\}}\\ \\ \overline{2a3bbb}=11\°\Longrightarrow 2-a+3-b+b-b=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow 5-a-b=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow a+b-5=11\°\\\\ \text{Si }a=0\text{ entonces:}\\ \overline{2a3bbb}=11\°\Longrightarrow b-5=11\°\\ \overline{2a3bbb}=11\°\Longrightarrow \boxed{b=5} \end{gathered}

6a(a+3)

=9\°⟹6+a+a+3=9\°

6a(a+3)

=9\°⟹2a+9=9\°

6a(a+3)

=9\°⟹a=9\°

Entonces

a∈{0,9}

2a3bbb

=11\°⟹2−a+3−b+b−b=11\°

2a3bbb

=11\°⟹5−a−b=11\°

2a3bbb

=11\°⟹a+b−5=11\°

Si a=0 entonces:

2a3bbb

=11\°⟹b−5=11\°

2a3bbb

=11\°⟹

b=5