Question

D=\frac{\left(x+3y\right)^2-\left(x-3y\right)^2}{xy}

Answer 1

Respuesta:

D=$\frac{\left(x+3y\right)^2-\left(x-3y\right)^2}{xy}$

$=\frac{12xy}{xy}$

$=12$

espero y te sirva :'3