Question

d) -2√5(-√5ײy+√2׳y²-4√5ײy³-1)​

Answer 1

Respuesta:

d) -2√5(-√5ײy+√2׳y²-4√5ײy³-1)​

Explicación paso a paso:

$=\left(-2\sqrt{5}\right)\left(-\sqrt{5}x^2y\right)+\left(-2\sqrt{5}\right)\sqrt{2}x^3y^2+\left(-2\sqrt{5}\right)\left(-4\sqrt{5}x^2y^3\right)+\left(-2\sqrt{5}\right)\left(-1\right)\\=2\sqrt{5}\sqrt{5}x^2y-2\sqrt{5}\sqrt{2}x^3y^2+2\times \:4\sqrt{5}\sqrt{5}x^2y^3+2\times \:1\times \sqrt{5}\\\\=10x^2y-2\sqrt{10}x^3y^2+40x^2y^3+2\sqrt{5}$