cuantos moles contiene un gas en CNPT si ocupa un volumen de 336 litros?
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CNT y P
T = 273 K = 0 ºC
P = 1 atm
V = 336 L
R = 0.0821 (L atm / mol K)
n = ?
LEY DE LOS GASES IDEALES:
V · P = n · R · T
n = 336 L · 1 atm
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0.0821 (L atm/mol K)· 273 K
n = 14.99 ≈ 15 moles de gas
T = 273 K = 0 ºC
P = 1 atm
V = 336 L
R = 0.0821 (L atm / mol K)
n = ?
LEY DE LOS GASES IDEALES:
V · P = n · R · T
n = 336 L · 1 atm
````````````````````````````````````````
0.0821 (L atm/mol K)· 273 K
n = 14.99 ≈ 15 moles de gas
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