Question

cuantos mol de Al(OH)3 se producen cuando se forman 6.0 mol de CH4


Al4C3+12H2O---------------4Al(OH)3+3CH4

Answer 1

                     Al4C3  +  12 H2O → 4 Al(OH)3 + 3 CH4

moles Al(OH)3 = 6.0 mol CH4  x  4 mol Al(OH)3
                                                    ``````````````````````
                                                        3 mol CH4

moles Al(OH)3 = 8