Question

Cuantos litros de H2 a TPN se producen a partir de 28.0 de Zing con un exceso de H2 SO4. Zn + H2 SO4 => Zn SO4 + H2

Answer 1

Mm Zn = 65.38 g/mol

1. calcular moles de hidrógeno

n H2 = 28.0 g Zn x 1 mol Zn x 1 mol H2

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65.38 g Zn 1 mol Zn

n H2 = 0.428 moles

2. calcular volumen

1 mol ---- 22.4 L H2

0.428 mol ----- x

x = 9.58 Litros de H2