cuantos gramos de NH3 se producen cuando reaccionan con 2.5g de N2 con suficiente H2.
N2 + H2 ------------> NH3
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Mn NH3 = 17 g/mol
N2 + 3 H2 = 2 NH3
g = 2.5 g N2 x 1 mol N2 x 2 mol NH3 x 17 g NH3
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14 g N2 3 mo N2 1 mol NH3
g = 2.02 gramos de NH3
N2 + 3 H2 = 2 NH3
g = 2.5 g N2 x 1 mol N2 x 2 mol NH3 x 17 g NH3
`````````````` `````````````` ````````````
14 g N2 3 mo N2 1 mol NH3
g = 2.02 gramos de NH3
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