Cuantos gramos de hidroxido de sodio se necesitan para neutralizar 392.32 g de acido sulfurico?
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2NaOH + H2SO4 → Na2SO4 + 2H2O
Mm NaOH = 40 g/mol
H2SO4 = 98 g/mol
g NaOH = 392.32 g H2SO4 x 1 mol H2SO4 x 2 mol NaOH x 40 g NaOH
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98 g H2SO4 1 mol H2SO4 1 mol NaOH
g NaOH = 320.26
Mm NaOH = 40 g/mol
H2SO4 = 98 g/mol
g NaOH = 392.32 g H2SO4 x 1 mol H2SO4 x 2 mol NaOH x 40 g NaOH
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98 g H2SO4 1 mol H2SO4 1 mol NaOH
g NaOH = 320.26
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