Question

¿cuánto es? el procedimiento por favor 1/25m²-1/49n²​

Answer 1

$\dfrac{1}{25m^{2} } -\dfrac{1}{49n^{2} }$

$\dfrac{1^{2} }{5^{2}m^{2} } -\dfrac{1^{2} }{7^{2}n^{2} }$

$\dfrac{1^{2} }{(5m^{2}) } -\dfrac{1^{2} }{(7n^{2}) }$

(1/5m)² -(1/7n)²

(1/5m-1/7n)(1/5m+1/7n)