Question

cuanto es 8+x-[7-9x+3(4x-5)]+3=0=

Answer 1

el resultado es X=9.......

Answer 2

8+x-[7-9x+3(4x-5)]+3=0

8+x-[7-9x+12x-15]+3 = 0

8+x-[3x-8]+3 = 0

8 + x -3x + 8 = 0

16 = 2x

$\frac{16}{2} = x$

8 = x