Question

cuanto es 5(x-1)+16(2x+3)=3(2x-7)-x con compropacion

Answer 1

Respuesta:

5x-5+32x+48=6x-21-x

5x+32x-6x+x= -21-48+5

32x= -64

x= -64÷32

x= -2

Answer 2

Hola! T_T

Resolvemos:

$\bf{5(x-1)+16(2x+3)=3(2x-7)-x} \\ \bf{5x - 5 + 32x + 48 = 6x - 21 - x} \\ \bf{37x + 43 = 6x - 21 - x} \\ \bf{37x + 43 = 5x - 21} \\ \bf{37x + 43 - 5x = - 21} \\ \bf{32x + 43 = - 21} \\ \bf{32x = - 21 - 43} \\ \bf{32x = - 64} \\ \bf{x = - \frac{64}{32} } \\ \boxed{ \bf{ \red{ x = - 2}}}$

La respuesta es x = - 2

Comprobación:

$\bf{5(x-1)+16(2x+3)=3(2x-7)-x} \\ \bf{5 \times (- 2 - 1) + 16 \times (2 \times - 2 + 3) = 3(2 \times - 2 - 7) + 2} \\ \bf{5 \times - 3 + 16 \times (2 \times - 2 + 3) = 3 \times(2 \times - 2 - 7) + 2 } \\ \bf{5 \times - 3+ 16 \times (-4+3) = 3 \times(-4-7)+2 } \\ \bf{5 \times - 3+ 16 × -1 = 3 × (-4-7)+2} \\ \bf{5 x - 3 + 16 × - 1 = 3 × - 11+2} \\ \bf{-15 + 16 × -1 - 3 \times -11+2} \\ \bf{-15 - 16 = 3 \times - 11+2} \\ \bf{- 15 - 16 = - 33 + 2} \\ \bf{- 31 = - 33 + 2} \\ \bf{- 31 = - 31}$

Se cumple la igualdad ✅.

Salu2