Question

cuánto es (2y²-2y+4y²-5) - (3y-6y³+8y³+ 4y²-5)​

Answer 1

Respuesta:

( 2y² - 2y + 4y² - 5 ) - ( 3y - 6y³ + 8y³ + 4y² - 5 )

$(6 {y}^{2} - 2y - 5) - (3y + 2 {y}^{3} + 4 {y}^{2} - 5) \\ 6 {y}^{2} - 2y - 5 - 3y - 2 {y}^{3} -4 {y}^{2} + 5 \\ - 2 {y}^{3} + 2 {y}^{2} - 5y$