Question

cuanto es (14-8×3)÷(9-11)+100÷(-8-2) separando en terminos, porfavor es para un examen​

Answer 1

Respuesta:

= -5

Explicación paso a paso:

$\left(14-8\times \:3\right)\div \left(9-11\right)+100\div \left(-8-2\right)\\\\=-10\div \left(9-11\right)+100\div \left(-8-2\right)\\\\=-10\div \left(-2\right)+100\div \left(-8-2\right)\\\\=-10\div \left(-2\right)+100\div \left(-10\right)\\\\=5+100\div \left(-10\right)\\\\=5-10\\\\=-5$