Cuantas moles de cada reactivo son necesarias para producir 240 kg Fe2O3?
4Fe+3O2------>2Fe2O3
Respuestas a la pregunta
Mm Fe2O3 = 159.68 g/mol
1. convertir Kg a g
1 Kg ---- 1000 g
240 Kg ---- x
x = 240000 g de Fe2O3
2. Calcular moles de hierro
moles Fe = 240000 g Fe2O3 x 1 mol Fe2O3 x 4 mol Fe
```````````````````` `````````````````
159.68 g Fe2O3 2 mol Fe2O3
moles Fe = 30060,01
2. calcular moles de O2
moles O2 = 240000 g Fe2O3 x 1 mol Fe2O3 x 3 mol Fe
```````````````````` `````````````````
159.68 g Fe2O3 2 mol Fe2O3
mol O2 = 2254,50
3. Calcular moles de Fe2O3
moles O2 = 240000 g Fe2O3 x 1 mol Fe2O3
````````````````````
159.68 g Fe2O3
moles O2 = 1503
Respuesta: espero
que sirva
Explicación:4 Fe + 3O2 → 2 Fe2O3
Mm Fe2O3 = 159.68 g/mol
1. convertir Kg a g
1 Kg ---- 1000 g
240 Kg ---- x
x = 240000 g de Fe2O3
2. Calcular moles de hierro
moles Fe = 240000 g Fe2O3 x 1 mol Fe2O3 x 4 mol Fe
```````````````````` `````````````````
159.68 g Fe2O3 2 mol Fe2O3
moles Fe = 30060,01
2. calcular moles de O2
moles O2 = 240000 g Fe2O3 x 1 mol Fe2O3 x 3 mol Fe
```````````````````` `````````````````
159.68 g Fe2O3 2 mol Fe2O3
mol O2 = 2254,50
3. Calcular moles de Fe2O3
moles O2 = 240000 g Fe2O3 x 1 mol Fe2O3
````````````````````
159.68 g Fe2O3
moles O2 = 1503