Cuántas mol g de nitrógeno se requiere para la combustión de 13 mol g de amoniaco
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2NH3 → 3H2 + N2
mol N2 = 13 mol NH3 x 1 mol N2
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2 mol NH3
mol N2 = 6.5
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no explica si son 13 mol o 13 gramos, ahora lo resuelvo con 13 g NH3
Mm NH3 = 17 g/mol
N2 = 28 g/mol
g N2 = 13 g NH3 x 1 mol NH3 x 1 mol N2 x 28 g N2
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17 g NH3 2 mol NH3 1 mol N2
g N2 = 10.70 g
mol N2 = 13 mol NH3 x 1 mol N2
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2 mol NH3
mol N2 = 6.5
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no explica si son 13 mol o 13 gramos, ahora lo resuelvo con 13 g NH3
Mm NH3 = 17 g/mol
N2 = 28 g/mol
g N2 = 13 g NH3 x 1 mol NH3 x 1 mol N2 x 28 g N2
``````````````` `````````````` ``````````````
17 g NH3 2 mol NH3 1 mol N2
g N2 = 10.70 g
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