Química, pregunta formulada por alepapa159osw4wz, hace 1 año

Cuántas mol g de nitrógeno se requiere para la combustión de 13 mol g de amoniaco

Respuestas a la pregunta

Contestado por snorye
1
                          2NH3  → 3H2 + N2

mol N2 = 13 mol NH3  x  1 mol N2
                                        ``````````````
                                        2 mol NH3

mol N2 = 6.5

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no explica si son 13 mol o 13 gramos, ahora lo resuelvo con 13 g NH3

Mm NH3 = 17 g/mol
          N2 = 28 g/mol

g N2 = 13 g NH3  x  1 mol NH3  x  1 mol N2  x  28 g N2
                                ```````````````    ``````````````   ``````````````
                                  17 g NH3    2 mol NH3    1 mol N2

g N2 = 10.70 g
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