Question

cuáles son los primeros diez terminos de una sucesión si el inicial es 2/3 y la diferencia entre dos términos consecutivos es 1/6​

Answer 1

Respuesta:

a₁ =  2/3

d = 1/6

a₂ = 2/3 + 1/6 = (4/6 + 1/6) = (4 + 1)/6 = 5/6

a₃ = 5/6 + 1/6 = (5 + 1)/6 = 6/6 = 1

a₄ = 1 + 1/6 = 6/6 + 1/6 = (6 + 1/6 = 7/6

a₅ = 7/6 + 1/6 = (7 + 1)/6 = 8/6

a₆ = 8/6 + 1/6 = (8 + 1)/6 = 9/6

a₇ = 9/6 + 1/6 = (9 + 1)/6 = 10/6

a₈ = 10/6 + 1/6 = (10 + 1)/6 = 11/6

a₉ = 11/6 + 1/6 = (11 + 1)/6 = 12/6 = 2

a₁₀ = 2 + 1/6 = 12/6 + 1/6 = (12 + 1)/6 = 13/6

2/3 . 5/6 . 1 . 7/6 . 8/6 . 9/6 . 10/6 . 11/6 . 2 . 13/6   Simplificando

2/3 . 5/6 . 1 . 7/6 . 4/3 . 3/2 . 5/3 . 11/6 . 2 . 13/6

Respuesta.

2/3 . 5/6 . 1 . 7/6 . 4/3 . 3/2 . 5/3 . 11/6 . 2 . 13/6

Explicación paso a paso: