Question

¿cual sera el volumen que ocupara 2g. de oxigeno a 20'C y 728torr ?

Answer 1

V x P = n x R x T

v = ?
m = 2 g
t = 20 + 273 = 293 K
P = 728 torr
1 atm --- 760 torr
   x      --- 728 torr

x = 0.96 atm

R= 0.0821 (atm L / mol K)
n (mol) = masa/Mm
Mm O2 = 32 g/mol

n = 2 g / 32 g/mol = 0.063 mol

v = n x R x T
     ````````````
           P
          
V = 0.063 mol x 0.0821 (atm L /mol K) x 293 K
     ````````````````````````````````````````````````````````````
                     0.96 atm

V = 1.578 Litros