¿cual sera el volumen que ocupara 2g. de oxigeno a 20'C y 728torr ?
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V x P = n x R x T
v = ?
m = 2 g
t = 20 + 273 = 293 K
P = 728 torr
1 atm --- 760 torr
x --- 728 torr
x = 0.96 atm
R= 0.0821 (atm L / mol K)
n (mol) = masa/Mm
Mm O2 = 32 g/mol
n = 2 g / 32 g/mol = 0.063 mol
v = n x R x T
````````````
P
V = 0.063 mol x 0.0821 (atm L /mol K) x 293 K
````````````````````````````````````````````````````````````
0.96 atm
V = 1.578 Litros
v = ?
m = 2 g
t = 20 + 273 = 293 K
P = 728 torr
1 atm --- 760 torr
x --- 728 torr
x = 0.96 atm
R= 0.0821 (atm L / mol K)
n (mol) = masa/Mm
Mm O2 = 32 g/mol
n = 2 g / 32 g/mol = 0.063 mol
v = n x R x T
````````````
P
V = 0.063 mol x 0.0821 (atm L /mol K) x 293 K
````````````````````````````````````````````````````````````
0.96 atm
V = 1.578 Litros
adrianana:
muchas muchas grasias
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