Question

cual es la suma del MCD de 48 y 24 con el MCM de 60 y 180

Answer 1

✎ Calculamos MCD de 48 y 24

Determinaremos el máximo común divisor(M.C.D.) por descomposición simultánea.

                                    $\begin{array}{c}\begin{array}{ccc|c}\blue{\boldsymbol{\sf{48}}}&&\blue{\boldsymbol{\sf{24}}}&\sf{2}\\\sf{24}&&\sf{12}&\sf{2}\\\sf{12}&&\sf{6}&\sf{2}\\\sf{6}&&\sf{3}&\sf{3}\\\sf{2}&&\sf{1}&\end{array}\\\\\begin{array}{c}\mathsf{M.C.D.(48, 24)=2\times2\times2\times3}\\\\\mathsf{M.C.D.(48, 24)=2^{3}\times3^{}}\\\\\boxed{\boldsymbol{\mathsf{M.C.D.(48, 24)=24}}}\end{array}\end{array}$

                               

✎ Calculamos MCM de 60 y 180

                                 $\begin{array}{c}\begin{array}{ccc|c}\blue{\boldsymbol{\sf{60}}}&&\blue{\boldsymbol{\sf{180}}}&\sf{2}\\\sf{30}&&\sf{90}&\sf{2}\\\sf{15}&&\sf{45}&\sf{3}\\\sf{5}&&\sf{15}&\sf{3}\\\sf{5}&&\sf{5}&\sf{5}\\\sf{1}&&\sf{1}&\end{array}\\\\ \begin{array}{c}\sf{M.C.M.(60, 180)=2\times2\times3\times3\times5}\\\\\mathsf{M.C.M.(60, 180)=2^{2}\times3^{2}\times5^{}}\\\\\boxed{\boldsymbol{\mathsf{M.C.M.(60, 180)=180}}}\end{array}\end{array}$

Nos piden

                       $\begin{array}{c}\sf{M.C.D.(48,24) + M.C.M.(60,180)=24+180}\\\\\boxed{\boxed{\boldsymbol{\red{\sf{M.C.D.(48,24) + M.C.M.(60,180)=204}}}}}\end{array}$

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