Question

cual es la respuesta de:

-(3(4-(7*2-3))-6(2/3+1)˄3)+4(9-1)˄0

Answer 1

$-(3(4-(7*2-3))-6( \frac{2}{3}+1)^3+4(9-1)^0= \\ \\ -(3(4-(14-3))-6( \frac{2}{3}+1)^3+4(8)^0= \\ \\ \textit{Todo numero elevado a la cero es UNO} \\ \\ -(3(4-(11)))-6( \frac{2}{3}+ \frac{3}{3})^3+4*1= \\ \\ -(3(- 7))-6( \frac{5}{3})^3+4= \\ \\ -(-21)-6( \frac{125}{27})+4= \\ \\21- \frac{250}{9}+4= \\ \\ 25 - \frac{250}{9}= \\ \\ \frac{225}{9} - \frac{250}{9}= \boxed{- \frac{25}{9} }$

Espero que te sirva, salu2!!!!