cual es la masa en gramos de una muestra de hipoclorito de sodio (naclo) que contienen 0,964 moles?(na: 23 u.m.a, cl: 35 u.m.a, o: 16 u.m.a
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NaClO
Mm:
Na = 1 x 23 = 23 g/mol
Cl = 1 x 35 = 35 g/mol
O = 1 x 16 = 16 g/mol
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Mm =74 g/mol
mol = masa / Mm
masa = mol x Mm
masa = 0.964 mol x 74 g/mol
masa = 71.336 g de NaClO
Mm:
Na = 1 x 23 = 23 g/mol
Cl = 1 x 35 = 35 g/mol
O = 1 x 16 = 16 g/mol
````````````````````````````````
Mm =74 g/mol
mol = masa / Mm
masa = mol x Mm
masa = 0.964 mol x 74 g/mol
masa = 71.336 g de NaClO
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