Question

cual es el volumen ocupado por 2,5 moles de nitrógeno a 1 520 torr de presión y 0° C?

Answer 1

Ley de los gases ideales

P x V = n x R x T

R =0.082 (L atm/ mol K)
T = 0 ºC + 273 = 27. K
P = 1520 torr
1 atm ----- 760 torr
   x     ----- 1520 torr

x = 1520 torr x 1 atm
      ```````````````````````
                  760 torr

x = 2 atm

n = 2.5 moles

calcular V = ?

V =  2.5 moles  x  0.082 (L  atm / mol K) x 273 K
      `````````````````````````````````````````````````````````````
                             2 atm

V = 27.98 L