Question

cual es el vértice de la parábola f(x)=×^2+2×+1​

Answer 1

$x = - \frac{b}{2a} = - \frac{2}{2(1)} = - 1$

$y = {( - 1)}^{2} + 2( - 1) + 1 = 1 - 2 + 1 = 0$

(-1,0)