Cuál es el ángulo comprendido entre los siguientes vectores?A = (7i – 4j)m y B = (5i + 2j)mC = (-5i + j)Km/h y D = (-8i - 12j)E = (6m; 30°) y F = (2i + 7j)m
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DATOS:
Cual es el angulo (α ) comprendido entre los vectores :
A y B
C y D
E y F
SOLUCION:
A= ( 7i - 4j ) m ΙA Ι = √ (7)² + ( 4)² = √65
B = ( 5i + 2 j) m Ι B Ι = √ (5)² + (2)² = √29
A . B = ( 7i - 4j ) . ( 5i + 2j ) = 35 - 8 = 27 .
A. B = ΙAΙ .ΙBΙ . Cos α
Cos α = A.B / ΙAΙ.ΙBΙ = 27 / (√65 *√29 ) = 0.6218
α = 51.54 °
C = ( -5i + j) Km/h ΙC Ι=√⁽-5⁾² +1 ² = √26
D =m ( - 8i - 12j ) Km/h Ι DΙ =√(-8)² + (-12)² = √208
C.D = (-5i +j) .(-8i-12j) = 40 - 12 =28
Cos α = C.D/ ΙCΙ.ΙDΙ= 28/(√26 *√208 ) =0.3807
α = 67.61°
E = ( 6 m ; 30° ) F= (2i + 7j) m
E = ( 6*cos 30°; 6 * sen 30° ) = (3√3 , 3) ΙEΙ= √ ( 3√3 )² + 3² = 6
F = 2i + 7j ΙFΙ =√ 2² +7² =√53
E.F = (3√3 ,3).(2i +7j) = 6√3 + 21 =31.39
Cosα = E.F /ΙEΙ.ΙFΙ= 31.39/( 6*√53 )= 0.7186
α = 44.05°
Cual es el angulo (α ) comprendido entre los vectores :
A y B
C y D
E y F
SOLUCION:
A= ( 7i - 4j ) m ΙA Ι = √ (7)² + ( 4)² = √65
B = ( 5i + 2 j) m Ι B Ι = √ (5)² + (2)² = √29
A . B = ( 7i - 4j ) . ( 5i + 2j ) = 35 - 8 = 27 .
A. B = ΙAΙ .ΙBΙ . Cos α
Cos α = A.B / ΙAΙ.ΙBΙ = 27 / (√65 *√29 ) = 0.6218
α = 51.54 °
C = ( -5i + j) Km/h ΙC Ι=√⁽-5⁾² +1 ² = √26
D =m ( - 8i - 12j ) Km/h Ι DΙ =√(-8)² + (-12)² = √208
C.D = (-5i +j) .(-8i-12j) = 40 - 12 =28
Cos α = C.D/ ΙCΙ.ΙDΙ= 28/(√26 *√208 ) =0.3807
α = 67.61°
E = ( 6 m ; 30° ) F= (2i + 7j) m
E = ( 6*cos 30°; 6 * sen 30° ) = (3√3 , 3) ΙEΙ= √ ( 3√3 )² + 3² = 6
F = 2i + 7j ΙFΙ =√ 2² +7² =√53
E.F = (3√3 ,3).(2i +7j) = 6√3 + 21 =31.39
Cosα = E.F /ΙEΙ.ΙFΙ= 31.39/( 6*√53 )= 0.7186
α = 44.05°
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