Question

considerando

A=3x²–2x+7

B=6x³–5x+2

C=5x²+4x–3

Calcular.

A+B+C, A–B–C, 2A–B+C, A–3B+2C



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Answer 1

Respuesta:

A+B+C= 6x³+8x²+7x+6

A-B-C = -6x³-2x²-x+8

2A-B+C= -6x³+11x²+5x+9

A-3B+2C= -18x³+13x²+21x-5

Explicación paso a paso:

A=3x²–2x+7

B=6x³–5x+2

C=5x²+4x–3

A+B+C

sustituimos

(3x²-2x+7)+(6x³-5x+2)+(5x²+4x-3)

ordenamos

6x³+3x²+5x²-2x+5x+4x+7+2-3

resolvemos

6x³+8x²+7x+6

A-B-C

(3x²-2x+7)-(6x³-5x+2)-(5x²+4x-3)

3x²-2x+7-6x³+5x-2-5x²-4x+3

-6x³+3x²-5x²-2x+5x-4x+7-2+3

-6x³-2x²-x+8

2A-B+C

2(3x²-2x+7)-(6x³-5x+2)+(5x²+4x-3)

6x²-4x+14-6x³+5x-2+5x²+4x-3

-6x³+6x²+5x²-4x+5x+4x+14-2-3

-6x³+11x²+5x+9

A-3B+2C

(3x²-2x+7)-3(6x³-5x+2)+2(5x²+4x-3)

3x²-2x+7-18x³+15x-6+10x²+8x-6

-18x³+3x²+10x²-2x+15x+8x+7-6-6

-18x³+13x²+21x-5