Question

con resolución
_____________'​

Answer 1

Respuesta: 5.75

Explicación paso a paso:

$U'(x)=\frac{d}{dx}\left(-0.0035x^3+0.07x^2+25x-200\right)\\\\U'(x)==-\frac{d}{dx}\left(0.0035x^3\right)+\frac{d}{dx}\left(0.07x^2\right)+\frac{d}{dx}\left(25x\right)-\frac{d}{dx}\left(200\right)\\\\U'(x)=-0.0105x^2+0.14x+25$

$U'(50)=-0.0105\left(50\right)^2+0.14\left(50\right)+25\\\\U'(50)=5.75$