Question

Composición porcentual de: HF, F2o, L2, CH2o

Answer 1

HF
Mm
H: 1 x 1 = 1 g/mol
F= 1 x 19 = 19 g/mol
``````````````````````````````
       Mm = 20 g/mol

H:  20 g ------ 100 %
        1 g .......  x

         x = 5 %

F:  20 g ------ 100 %
       19 g .......  x

         x = 95 %


F2O
Mm
O: 1 x 16 = 16 g/mol
F= 2 x 19 = 38 g/mol
``````````````````````````````
       Mm = 54 g/mol

O:  54 g ------ 100 %
      16 g .......  x

         x = 29,63 %

F:  54 g ------ 100 %
     38 g .......  x

         x = 70.37 %

CH2O
Mm
C: 1 x 12 = 12 g/mol
H: 2 x1 = 2 g/mol
O: 1 x 16 g/mol = 16 g/mol
````````````````````````````````````````
   Mm = 30 g/mol

C: 30 g ------ 100 %
     12 g ------  x

   x = 40%

H: 30 g ----- 100 %
       2 g -----  x

   x = 6.667 %

O: 30 g ---- 100 %
     16 g -----  x

     x = 53.33 %

no resolvi el L2 indica que es???