Question

Composición porcentual de:
Ca(OH)2
H3PO4
C6H12O6

Answer 1

Mm Ca(OH)2

Ca: 1 x 40 = 40 g/mol
 H: 1 x 2 = 2 g/mol
 O:  2 x 16 = 32 g/mol
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           Mm =74 g/mol

calcio:
74 g -------- 100%
40 g --------- x
x = 54.5 % de Ca

hidrogeno:
 74 g -------- 100%
2 g --------- x
x = 2.70 % de H

Oxigeno:
74 g -------- 100%
32 g --------- x
x = 43.24 % de O

b) Mm  H3PO4
H: 3 x 1 = 3 g/mol
P: 1 x 31 = 31 g/mol
O: 4 x 16 = 64 g/mol
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         Mm = 98 g/mol

HIDROGENO:

98 g ---- 100 %
  3 g -----  x
x = 3.06 % H

FOSFORO:

98 g ---- 100 %
31 g -----  x
x = 31.63 % P

OXIGENO:



c) Mm C6H12O6

C: 6 x 12 = 72 g/mol
 H: 12 x 1 = 12 g/mol
O: 6 x16 = 96 g/mol
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           Mm = 180 g/mol

CARBONO:
180 g ---- 100 %
 72 g -----  x

x = 40 % C

HIDROGENO:

180 g ---- 100 %
 12 g -----  x

x = 6.67 %  H

OXIGENO:

180 g ---- 100 %
  96 g -----  x

x = 53.33 % O

Answer 2

Respuesta:

Explicación: