Compocision porcentual hidróxido de potasio
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KOH
calcular masa molecular
K: 1 x 39 = 39 g/mol
O: 1 x 16 = 16 g/mol
H: 1 x 1 = 1 g/mol
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Mm = 56 g/mol
Potasio:
56 g ---- 100 %
39 g ---- x
x = 69.64 % K
Oxigeno:
56 g ----- 100 %
16 g ----- x
x = 28.57 % O
Hidrógeno:
56 g ---- 100 %
1 g ---- x
x = 1.79 % H
calcular masa molecular
K: 1 x 39 = 39 g/mol
O: 1 x 16 = 16 g/mol
H: 1 x 1 = 1 g/mol
````````````````````````````````
Mm = 56 g/mol
Potasio:
56 g ---- 100 %
39 g ---- x
x = 69.64 % K
Oxigeno:
56 g ----- 100 %
16 g ----- x
x = 28.57 % O
Hidrógeno:
56 g ---- 100 %
1 g ---- x
x = 1.79 % H
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