como se resuelve 5x(3x+20)= x(2x+3)?
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5x(3x+20)= x(2x+3)
15x^2+100x=2x^2+3x
15x^2-2x^2=-100x+3x
13x^2=-97x
15x^2+100x=2x^2+3x
15x^2-2x^2=-100x+3x
13x^2=-97x
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5x(3x+20)= x(2x+3)
15(x)^2 +100x = 2(x)^2 +3x
15(x)^2 +100x -2(x)^2 -3x = 0
13(x)^2 +97x = 0
(x)^2 +(97/13)x =0
(x)^2 +(97/13)x +(97/26)^2 = (97/26)^2
(x +(97/26))^2 = (97/26)^2
x+ (97/26) = (97/26) x+ (97/26) = -(97/26)
x = (97/26) - (97/26) x= -(97/26) -(97/26)
x= 0 x= -194/26 = -97/13
15(x)^2 +100x = 2(x)^2 +3x
15(x)^2 +100x -2(x)^2 -3x = 0
13(x)^2 +97x = 0
(x)^2 +(97/13)x =0
(x)^2 +(97/13)x +(97/26)^2 = (97/26)^2
(x +(97/26))^2 = (97/26)^2
x+ (97/26) = (97/26) x+ (97/26) = -(97/26)
x = (97/26) - (97/26) x= -(97/26) -(97/26)
x= 0 x= -194/26 = -97/13
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