Question

como resolver derivadas algebraicas de f(x)=x½+x⅓​

Answer 1

Respuesta:

F(X) = X^(1/2)+X^(1/3)

F ' (X) = d/dx [ X^(1/2)+X^(1/3) ]

F ' (X) = d/dx [ X^(1/2) ] + d/dx [ X^(1/3) ]

F ' (X) = (1/2)X^((1/2)-1)+(1/3)X^((1/3)-1)

F ' (X) = (1/2)X^(-1/2) + (1/3)X^(-2/3)

F ' (X) = 1/(2X^(1/2))+1/(3X^(2/3))

F ' (X) = 1/(2√(x))+1/(3∛(x)^2)

F ' (X) = (1/(2√(x))+(1/(3∛(x)^2))

R// " F ' (X) = (1/(2√(x))+(1/(3∛(x)^2)) " es la derivada de la función " F(X) = X^(1/2)+X^(1/3) " .

Explicación paso a paso: