Question

como resolver 2 ^ x + 4 ^ x - 272 = 0​

Answer 1

${2}^{x} + {4}^{ x} - 2720$

${2}^{2} + ( {2}^{2} ) ^{x} - 272 = 0$

${2}^{x} + ( {2}^{x} )^{2} - 272 = 0$

$t + {t}^{2} - 272 = 0$

$t = - 17 \\ t = 16$

${2}^{x} = - 17 \\ {2}^{x} = 16$

x = 4

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