Question

Como puedo resolver esta ecuacion?

Answer 1

2ax - x² = -4a²
-x² +2ax - 4a²=0

Formula general

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Donde:
a = -1
b =2a
c=4a²


$x_{1,\:2}=\frac{-2a\pm \sqrt{\left(2a\right)^2-4\left(-1\right)4a^2}}{2\left(-1\right)}$


$x_{1,\:2}=\frac{-2a\pm \sqrt{16a^2+\left(2a\right)^2}}{-2}$


$x_{1,\:2}=\frac{-2a\pm2\sqrt{5}a}{2}$


$x_{1,\:2}=\-a\pm\sqrt{5}a$


$x_{1} =-\left(\sqrt{5}-1\right)a$

$x_{2} =\left(1+\sqrt{5}\right)a$