como calculo estas derivadas de funciones
Respuestas a la pregunta
Explicación:
1.- f(x)=5
f'(x)=d/dx(5)
=f'(x)=0
2.- f(x)=-2x
f'(x)=d/dx(-2x)
=f'(x)=-2
3.- f(x)=-2x+2
f'(x)=d/dx(-2x+2)
f'(x)=d/dx(-2x)+d/dx(2)
f'(x)=-2+0
=f'(x)=-2
4.- f(x)=-2x²-5
f'(x)=d/dx(-2x²-5)
f'(x)=d/dx(-2x²)-d/dx(5)
f'(x)=-2×2x-0
=f'(x)=-4x
5.-f(x)=2x⁴+x³-x²+4
f'(x)=d/dx(2x⁴+x³-x²+4)
f'(x)=d/dx(2x⁴)+d/dx(x³)-d/dx(x²)+d/dx(4)
f'(x)=2×4x³+3x²+2x+0
=f'(x)=8x³+3x²-2x
6.-f(x)=2x^7-3x^6+3x^3-4x^2-7
f'(x)=d/dx(2x^7-3x^6+3x^3-4x^2-7)
f'(x)=d/dx(2x^7)+d/dx(-3x^6)+d/dx(3x^3)+d/dx(-4x^2)-d/dx(7)
f'(x)=2×7x^6-3×6x^5+3×3x^2-4×2x-0
=f'(x)=14x^6-18x^5+9x^2-8x
1.- f(x)=-7
f'(x)=d/dx(-7)
=f'(x)=0
2.- f(x)=-7x
f'(x)=d/dx(-7x)
=f'(x)=-7
3.- f(x)=-5x+2
f'(x)=d/dx(-5x+2)
f'(x)=d/dx(-5)+d/dx(2)
f'(x)=-5+0
=f'(x)=-5
4.-f(x)=x^5-x^3+3
f'(x)=d/dx(x^5-x^3+3)
f'(x)=d/dx(x^5)-d/dx(x^3)+d/dx(3)
f'(x)=5x^4-3x^2+0
=f'(x)=5x^4-3x^2
5.-f(x)=2x^7-3x^6+3x^3-4x^2-7
f'(x)=d/dx(2x^7-3x^6+3x^3-4x^2-7)
f'(x)=d/dx(2x^7)+d/dx(-3x^6)+d/dx(-4x2)-d/dx(7)
f'(x)=2×7x^6-3×6x^5+3×3x^2-4×2x-0
=f'(x)=14x^6-18x^5+9x^2-8x
6.-f(x)=-3/2x³+2/5x²-4
f'(x)=d/dx(-3/2x³+2/5x²-4)
f'(x)=d/dx(-3/2x³)+d/dx(2/5x²)-d/dx(4)
f'(x)=-3/2×3x²+2/5×2x-0
=f'(x)=-9/2x²+4/5x
7.-f(x)=3/x²
f'(x)=d/dx(3/x²)
f'(x)=-3×d/dx(x²)/(x²)²
f'(x)=-3×2x/(x²)²
=f'(x)=-6/x³
8.-f(x)=-2/x³+3/x²-4x
f'(x)=d/dx(-2/x³+3/x²-4x)
f'(x)=-d/dx(2/x³)+d/dx(3/x²)+d/dx(-4x)
f'(x)=-(-2×3x²/(x³)²)-3×2x/(x²)-4
=f'(x)=6/x⁴-6/x³-4