Question

como calculo el volumen de KCLO3​

Answer 1

Respuesta:

Mm KCl = 74.5 g/mol

      KClO3 = 122.5 g/mol

g = 1 x 1000 = 1000 g

moles = masa /Mm

moles KCl  = 1000 g  x  1 mol KCl

                                      ````````````

                                      74.5 mo KCl

moles KCl = 13.42

g KClO3 = 13.42 mol KCl  x   2 mol KClO3  x  122.5 g KClO3

                                              ```````````````````    ``````````````````

                                               2 mol KCl          1 mol KClO3

g KClO3 = 1643,95

moles O2 = 13.42 mol KCl  x 3 mol O2

                                             ````````````

                                            2 mol KCl

mole O2 = 20.13

V x P = n x R x T

CN = P = 1 atm y T = 273 K

R = 0.0821 (atm L/mol K)

V = n x R x T

      ````````````

          P

V = 20.13 mol x  0.0821 (atm L/mol K) x 273 K

      ````````````````````````````````````````````````````````

                        1 atm

V = 451.18 Litros

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