Question

Circunferencia para completar los binomios X2+y2+2x-8y-8=0

Answer 1

Completando cuadrados será:
${x}^{2} + {y}^{2} + 2x - 8y - 8 = 0 \\ \\ ( {x}^{2} + 2x) + ( {y}^{2} - 8y) - 8 = 0 \\ \\( {(x + 1)}^{2} - 1) + ({(y - 4)}^{2} - 16) - 8 = 0 \\ \\ {(x + 1)}^{2} + {(y - 4)}^{2} - 1 - 16 - 8 = 0 \\ \\ {(x + 1)}^{2} + {(y - 4)}^{2} = 25 \\ \\ {(x + 1)}^{2} + {(y - 4)}^{2} = {5}^{2}$