Question

Circuito Mixto Por favor es muy urgente​

Answer 1

Respuesta:

Explicación:

Resistencia equivalente de $R_{2}$ y $R_{3}$ será $R_{23}$

$\frac{1}{R_{23}} = \frac{1}{R_{2}} +\frac{1}{R_{3}}$

$\frac{1}{R_{23}} = \frac{1}{4} +\frac{1}{12}$

$R_{23} =$ 3 Ω

$R_{total} = R_{1} + R_{23} + R_{4}$

$R_{total}$ = 8 Ω + 3 Ω + 5 Ω

$R_{total}$ = 16 Ω

$I_{total}$ = 16 Ω/30 v

$I_{total}$ = 0,533 A

$P_{total}$ = V.$I_{total}$ = 30*0,533

$P_{total}$ = 16 W

$V_{1}$ = $I_{t}*R_{1}$ = 0,533*8

$V_{1}$ = 4,26 v

$V_{4}$ = $I_{t}*R_{4}$ = 0,533*5

$V_{4}$ = 2,67 v

$V_{1}+V_{23}+V_{4} = V_{t}$

4,26 + $V_{23}$ + 2,67 = 30

$V_{23}$ = 23,07 v

$I_{1} = I_{total}$

$I_{2} =\frac{R_{2}}{V_{23}} = \frac{4}{23,07}$

$I_{2} =$ 0,17

$I_{3} =\frac{R_{3}}{V_{23}} = \frac{12}{23,07}$

$I_{3} =$ 0,52 A

$I_{4} = I_{total}$