Charges a and b in the figure are equal. Exerts a force on the other of magnitude. Suppose the charge of b si increased by a factor of 4, but everything else is unchanged
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To the charges A and B, The force on B is: 4F
To the charges A and B in the figure qA=qB and exerts a force on the other of magnitude, suppose the charge of B is increased by a factor of 4 : 4qB, but everything else is unchanged, then:
qA=qB
d
4qB
Coulomb law
F = K*qA*qB/d²
F' = K*qA*4qB/d² = 4* K*qA*qB/d²
F'= 4F
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