calculo de la masa atomica molecular de la sustancia carbonata de paladio cuya formula es PdC2
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PdC2
Pd = 1 x 106.42 = 106.42 g/mol
C= 2 x 12 = 24 g/mol
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Mm = 130.42 g/mol
Pd = +2, +4
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Pd2C = carburo de paladio (II)
Pd: 2 x 160.42 = 212.84 g/mol
C: 1 x 12 = 12 g/mol
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Mm = 224.84 g/mol
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PdC / carburo de paladio (IV)
Pd: 106.42 x 1 = 106.42 g/mol
C: 12 x 1 = 12 g/mol
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Mm = 118.42 g/mol
Pd = 1 x 106.42 = 106.42 g/mol
C= 2 x 12 = 24 g/mol
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Mm = 130.42 g/mol
Pd = +2, +4
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Pd2C = carburo de paladio (II)
Pd: 2 x 160.42 = 212.84 g/mol
C: 1 x 12 = 12 g/mol
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Mm = 224.84 g/mol
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PdC / carburo de paladio (IV)
Pd: 106.42 x 1 = 106.42 g/mol
C: 12 x 1 = 12 g/mol
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Mm = 118.42 g/mol
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