Question

calculo de la formula minima y molecular A)c=40% o=53,4% H=6,6%

Answer 1

C: 40 g/ 12 g/mol = 3.33 mol
H: 6.6 g / 1 g/mol = 6.6 mol
O: 53.4 g / 16 g/mol = 3.33

dividir

C: 3.33 mol / 3.33 mol = 1
H:  6.6 mol / 3.33 mol = 2
O: 3.33 mol / 3.33 mol = 1

FE: CH2O