Calcúlese la densidad del H2S gaseoso (M = 34.1 kg/kmol) a 27 °C y 2.00 atm, considerándolo como gas
ideal.
Resp. 2.76 kg/m3
Alguien conoce el procedimiento correcto para llegar a la densidad?
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P x V = n x R x T
D = m/v
R = 0.0821 (atm L /mol K)
T = 27 + 273 = 300 K
P = 2.00 atm
Mm = 34.1 Kg/kmol
APLICAR FORMULAS:
n = m/Mm
P x V = (m/Mm) x R x T
P x V = m x R x T
````````````````
Mm
D = 2.00 X 34.1 Kg/Kmol
````````````````````````````````````
0.0821 (atm L/molK) x 300 K
D = 2.768 Kg/m3
D = m/v
R = 0.0821 (atm L /mol K)
T = 27 + 273 = 300 K
P = 2.00 atm
Mm = 34.1 Kg/kmol
APLICAR FORMULAS:
n = m/Mm
P x V = (m/Mm) x R x T
P x V = m x R x T
````````````````
Mm
P=(w/V)*R*T/PM
D = m/v
P = D x R x T / Mm
D = P x Mm / (R x T)D = 2.00 X 34.1 Kg/Kmol
````````````````````````````````````
0.0821 (atm L/molK) x 300 K
D = 2.768 Kg/m3
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