Calcule las temperaturas de ebullición y congelación al disolver 34g de azufre molecular en 100ml de etanol. El etanol tiene una densidad de 0,8 g/mol obten paralelamente la presión osmótica de la solución calculada a 25°C
Respuestas a la pregunta
Contestado por
248
Mm AE = 46 g/mol (AE= alcohol etilico)
d = m/v
m = d x v
m = 0.8 g/mL X 100 mL = 80 g de alcohol
m = 80 / 1000 = 0.08 Kg
calcular moles
mol = masa/Mm
mol = 34 g/ 46 g/mol = 0.739 mol
m = mol soluto / m Kg svte
m = 0.739 mol / 0.08 Kg
m = 9.23 mol/Kg svte
PTO DE ebullición
Δte = m x Ke
Δte = 9.23 mol / Kg x 0.52 mol /Kg ºC
Ate = 4.8 ºC
Te = 100 ºc + Δte
Te = 100 + 4.8 = 104.8 ºC
PTO. CONGELACION
Δtc = m x Kc
Δtc = 9.23 mol / Kg x 1.86 mol /Kg ºC
Atc = 17.16 ºC
Tc = 0 ºc - Δtc
Te = 0 ºC - 17.16 = -17.16 ºC
PRESION OSMOTICA:
M = mol/V(L)
mol = 34 g/32 g/mol
mol = 1.06
M = 1.06 mol / 0.1 L
M = 10.6 mol/L
T = 25 + 273 = 298 K
π = mol/v x R xT
π = 10.6 mol /L x 0.0821 (atm L/mol K) x 298 K
π = 259.33 atm
d = m/v
m = d x v
m = 0.8 g/mL X 100 mL = 80 g de alcohol
m = 80 / 1000 = 0.08 Kg
calcular moles
mol = masa/Mm
mol = 34 g/ 46 g/mol = 0.739 mol
m = mol soluto / m Kg svte
m = 0.739 mol / 0.08 Kg
m = 9.23 mol/Kg svte
PTO DE ebullición
Δte = m x Ke
Δte = 9.23 mol / Kg x 0.52 mol /Kg ºC
Ate = 4.8 ºC
Te = 100 ºc + Δte
Te = 100 + 4.8 = 104.8 ºC
PTO. CONGELACION
Δtc = m x Kc
Δtc = 9.23 mol / Kg x 1.86 mol /Kg ºC
Atc = 17.16 ºC
Tc = 0 ºc - Δtc
Te = 0 ºC - 17.16 = -17.16 ºC
PRESION OSMOTICA:
M = mol/V(L)
mol = 34 g/32 g/mol
mol = 1.06
M = 1.06 mol / 0.1 L
M = 10.6 mol/L
T = 25 + 273 = 298 K
π = mol/v x R xT
π = 10.6 mol /L x 0.0821 (atm L/mol K) x 298 K
π = 259.33 atm
Otras preguntas