Question

-calcule la masa molar de cada una de las siguientes sustancias.
a)perclorato de bario
b)sulfato de magnesio
c)cloruro de plomo(II)
d)nitrato de cobre(II)
e)cloruro de estaño(IV)
f)fenol,C6H6O
g)sulfuro de amonio((NH4)2S
h)diclorofenol,C6HOCI2
i)hidruro de bario,BaH2
j)fosfato diacido de potasio,KH2PO4
k)fosfato acido de potasio,K2HPO4
l)fosfato de potasio,K3PO4

Answer 1

a)perclorato de bario =  Ba(ClO4)2
Ba: 1 x 137 = 137 g/mol
Cl= 2 x 35.5 = 71 g/mol
O: 8 x 16 = 128 g/mol
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            Mm = 336 g/mol

b) MgSO4
Mg: 1 x 24 = 24 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
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         Mm = 120 g/mol

c) PbCl2
Pb: 1 x 207 = 207 g/mol
Cl: 2 x 35.5 = 71 g/mol
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              Mm = 278 g/mol

d) Cu(NO3)2
Cu: 1 x 63.5 = 63.5 g/mol
 N:  2 x 14 = 28 g/mol
 O: 6 x 16 = 96 g/mol
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         Mm = 187.5 g/mol

e)  SnCl4
Sn: 1 x 118.7 = 118.7 g/mol
Cl: 4 x 35.5 = 142 g/mol
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             Mm = 260.7 g/mol

f) C6H6O
C: 6 x 12 = 72 g/mo
H: 6 x 1 = 6 g/mol
O; 1 x 16 = 16 g/mol
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         Mm = 94 g/mol

g)  (NH4)2S

N: 2 x 14 = 28 g/mol
H: 8 x 1 = 8 g/mol
S: 1 X 32 = 32 g/mol
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          Mm = 68 g/mol

h)  C6HOCI2 
C: 6 x 12 = 72 g/mol
H: 1 x 1 = 1 g/mol
O: 1 x 16 = 16 g/mol
Cl: 2 x 35.5 = 71 g/mol
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           Mm = 160 g/mol

i)   BaH2
Ba: 1 x 137 = 137 g/mol
 H: 2 x 1 = 2 g/mol
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         Mm = 139 g/mol


j)  KH2PO4
K: 1 x 39 = 39 g/mol
H: 2 x 1 = 2 g/mol
P: 1 x 31 = 31 g/mol
O: 4 x 16 = 64 g/mol
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       Mm = 136 g/mol


k)  K2HPO4
K: 2 x 39 = 78 g/mol
H: 2 x 1 = 2 g/mol
P: 1 x 31 = 31 g/mol
O: 4 x 16 = 64 g/mol
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       Mm = 175  g/mol


l)  K3PO4
K: 3 x 39 = 117 g/mol
P: 1 x 31 = 31 g/mol
O: 4 x 16 = 64 g/mol
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       Mm = 212 g/mol