Question

Calcule el valor de:

a. 5/8
b. -3/8
c. 1
d. 8/7
e. 1/8

Answer 1

$\frac{2tan^2(495)}{sen^2(120)+2cos(300)} =\frac{2[-tan(45)]^2)}{sen^2(60)+2cos(60)} \\\\ \frac{2[1]}{(\frac{\sqrt{3} }{2})^2+2(\frac{1}{2}) } =\frac{2}{(\frac{3}{4})+(\frac{4}{4} ) } =\frac{2(4)}{7}=\frac{8}{7}$