Question

Calcule el peso de 1 litro de amoniaco geseoso en C.N.

Answer 1

Calcule el peso de 1 litro de amoniaco geseoso en C.N.

Mm NH3 = 17 g/mol

1. calcular moles de NH3

1 mol --- 22.4 L

x --- 1 L

x = 0.045 moles NH3

2. Calcular gramos de NH3

n = masa/Mm despejar masa

masa = 0.045 mol x 17 g/mol

masa = 0.76 g de NH3

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Aplicar la Ley de los Gases Ideales

V x P = n x R x T ; n = masa/Mm sustituir

V x P = m/Mm x R x T Despejar masa

masa (m) = (V x P x Mm) / R x T

Mm NH3 = 17 g/mol

P = 1 atm

R = 0.0821 (L atm/mol K)

T = 273 K

V = 1 L

masa = ( 1 L x 1 atm x 17 g/mol ) / (0.0821 (L atm/mol K) x 273 K )

masa = 0.759 g de NH3 ≈ 0.76 g NH3